По формуле сокращенного умножения разность квадратов
Касательная проходит через точки (-7;1) и (-2;-9)
1=-7k+c
-9=-2k+c
отнимем
10=-5k
k=-2
f`(x0)=k
f`(x0)=-2
Sin²a+cos²a=1
sin²a=1-cos²a
sin²a=1-(-4/5)²=1-16/25=9/25
sina=3/5 2 четверть(sina>0)
Ответ 3/5
Platit: 2 na 0 =1, tak kak 5 na 0 = 1, 10 na 0 = 1, poka a ne rovno 0 i a na 0 =1.
V našom priklade budet:
5-x = 2 na 0
5-x = 1, x = 5-1, x =4
1.1)=3(a+2b)
2)=4(3m-4n)
3)=5c(2k-3p)
4)=8a(x+1)
5)=5b(1-5c)
6)=7x(2x+1)
7)=n^5(n^5-1)
8)=m^6(1+m)
2.1)=266256-516*513=1548
2)0,343+0,7*0,51=0,7
3)0,0016-0,0088*1,2=-0,00896
3. 1)D=<span><span><span><span>(<span>−1</span>)^</span>2</span>−<span><span>4·1</span>·0</span></span>=<span>1−0</span></span>=<span>1
x1=-(-1)+1/2*1=2/2=1
x2=-(-1)-1/2*1=0/2=0
2)D=</span><span><span><span>15^2</span>−<span><span>4·1</span>·0</span></span>=<span>225−0</span></span>=<span>225=15
x1=-15+15/2*1=0/2=0
x2=-15-15/2*1=-30/2=-15
3)D=</span><span><span><span><span><span>(<span>−30</span>)^</span>2</span>−<span><span>4·5</span>·0</span></span>=<span>900−0</span></span>=900=30
x1=-(-30)+30/2*5=60/10=6
x2=-(-30)-30/2*5=0/10=0
4)</span><span><span><span><span>18^2</span>−<span><span>4·14</span>·0</span></span>=<span>324−0</span></span>=324=18
x1=-18+18/2*14=0/28=0
x2=-18-18/2*14=-36/28=-1,28</span>