Sqr(cos(b)) + (a*a + b*b + c*c) / (sin(a) + b * cos(b*b)) + e(a + b)
(cos(b) + sin(a)) * sin(a*a) + abs(log(a)) / (sin(a*a*a*a*a) + cos(b*b))
Ответ:
#include <iostream>
#include <string>
#include <sstream>
using namespace std;
template <typename T>
std::string toString(T val)
{
std::ostringstream oss;
oss<< val;
return oss.str();
}
template<typename T>
T fromString(const std::string& s)
{
std::istringstream iss(s);
T res;
iss >> res;
return res;
}
int main()
{
string number;
short int param;
cin >> param;
char i1,i2,i3,i4,i5,i6;
long long i,counter;
counter =0;
for(i=100000;i<=999999;i++){
number= toString(i);
i1 = number[0] ;
i2 = number[1] ;
i3 = number[2] ;
i4 = number[3] ;
i5 = number[4];
i6 = number[5];
if((i1+i2+i3) == (i4+i5+i6) && (i4+i5+i6) == param) {
cout << i1+i2+i3 <<" = "<<i4+i5+i6<<endl;
counter++;}
}
cout << counter;
return 0;
}
Объяснение:
Var top, sum, An, An1 :integer;
Begin
read(top);
sum:=2;
An:=1;
An1:=1;
repeat
An := An + An1;
An1 := An - An1;
sum := sum + An;
write(An:6)
until sum >= top
End.
Const
n = 10;
var
i, c: integer;
a, w: array[1..n] of integer;
begin
randomize;
writeln('Исходный массив:');
for i := 1 to n do
begin
a[i] := random(201) - 100;
write(a[i], ' ');
end;
writeln;
c := 0;
for i := 1 to n do
if a[i] > 0 then
begin
c := c + 1;
w[c] := a[i];
end;
writeln('Кол-во положительных элементов: ', c);
for i := 1 to n do
begin
if a[i] <= 0 then
begin
c := c + 1;
w[c] := a[i];
end;
end;
writeln('Результат:');
for i := 1 to c do
write(w[i], ' ');
end.